## Introductory Algebra for College Students (7th Edition)

$16y^2-24y+9$
Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $(4y-3)^2 ,$ is \begin{array}{l}\require{cancel} (4y)^2-2(4y)(3)+(3)^2 \\\\= 16y^2-24y+9 .\end{array}