Answer
$x^2-y^2+6x+9$
Work Step by Step
First we use the Sum and Difference of Two Terms:
$[(x+3)-y][(x+3)+y]$
$=(x+3)^2-y^2.$
Then we use the Square of a Binomial:
$(x+3)^2-y^2$
$=x^2+6x+9-y^2$
$=x^2-y^2+6x+9.$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 95
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