Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set: 51

Answer

$9y^2-24y+16$

Work Step by Step

Using $(a\pm b)^2=a^2\pm2ab+b^2$ or the square of a binomial, the square of the given expression, $ (3y-4)^2 ,$ is \begin{array}{l}\require{cancel} (3y)^2-2(3y)(4)+(4)^2 \\\\= 9y^2-24y+16 .\end{array}
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