Answer
$81x^4-72x^2+16$
Work Step by Step
First we apply the Sum and Difference of Two terms:
$[(3x+2)(3x-2)]^2$
$=[(3x)^2-2^2]^2$
$=(9x^2-4)^2$
Then we apply the Square of a Binomial:
$(9x^2-4)^2$
$=(9x^2)^2-2(9x^2)(4)+4^2$
$=81x^4-72x^2+16.$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 90
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