Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 636: 27

{$-243,32$}

Since, $u^2+u-6=0$ Factorize the expression as follows: $(u+3)(u-2)=0$ or, $u=${$-3,2$} Replace $u$ with $x^{1/5}$, we have $x^{1/5}=-3\implies x=-3^5$ $x=-243$ and $x^{1/5}=2\implies x=2^5$ $x=32$ Hence, our solution set is $x=${$-243,32$}