Intermediate Algebra for College Students (7th Edition)

$\bf{Graph (f)}$
We have $(x+2)^2-9(x+2)+20=0$ This implies $[(x+2)-4][(x+2)-5]=0$ Now, $(x+2)-4=0$ or, $x=2$ and $(x+2)-5=0$ or, $x=3$ To find the $x$-intercepts, we will have to take $f(x)=0$ Therefore, Our desired $x$-intercepts are: {$2,3$}; which represents the $\bf{Graph (f)}$