#### Answer

$\bf{Graph (f)}$

#### Work Step by Step

We have $(x+2)^2-9(x+2)+20=0$
This implies $[(x+2)-4][(x+2)-5]=0$
Now, $(x+2)-4=0$
or, $x=2$
and $(x+2)-5=0$
or, $x=3$
To find the $x$-intercepts, we will have to take $f(x)=0$
Therefore,
Our desired $x$-intercepts are: {$2,3$}; which represents the $\bf{Graph (f)}$