Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 636: 31

Answer

{$-8,-2,1,4$}

Work Step by Step

Since, $u^2+5u-14=0$ Factorize the expression as follows: $(u+7)(u-2)=0$ or, $u=${$-7,2$} Replace $u$ with $(x-\dfrac{8}{x})$, we have $(x-\dfrac{8}{x})=-7$ or, $x^2+7x-8=0$ or,$(x+8)(x-1)=0$ or, $x=${$-8,1$} and $(x-\dfrac{8}{x})=2$ or, $x^2-2x-8=0$ or,$(x+2)(x-4)=0$ or, $x=${$-2,4$} Hence, our solution set is $x=${$-8,-2,1,4$}
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