Answer
$\bf{Graph (e)}$
Work Step by Step
We have $x^{1/3}+2x^{1/6}-3=0$
This implies $(x^{1/6}+3)(x^{1/6}-1)=0$
Thus, $x^{1/6}=-3$, which has no solution
and $x^{1/6}=1$
or, $x=1$
To find the $x$-intercepts, we will have to take $f(x)=0$
Therefore,
Our desired $x$-intercepts are: {$1$}; which represents the $\bf{Graph (e)}$
