Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 636: 30

Answer

{$81$}

Work Step by Step

Since, $2u^2-5u-3=0$ Factorize the expression as follows: $(2u+1)(u-3)=0$ or, $u=${$-\dfrac{1}{2},3$} Replace $u$ with $x^{1/4}$, we have $x^{1/4}=-\dfrac{1}{2}$ ; which has no solution and $x^{1/4}=3\implies x=3^4$ $x=81$ Hence, our solution set is $x=${$81$}
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