Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 636: 28

{$-32,1$}

Since, $u^2+u-2=0$ Factorize the expression as follows: $(u+2)(u-1)=0$ or, $u=${$-2,1$} Replace $u$ with $x^{1/5}$, we have $x^{1/5}=-2\implies x=-2^5$ $x=-32$ and $x^{1/5}=1\implies x=1^5$ $x=1$ Hence, our solution set is $x=${$-32,1$}