Answer
{$-8,\dfrac{1}{8}$}
Work Step by Step
Plug $f(x)=2$
Therefore, we have $2x^{2/3}+3x^{1/3}=2$
This implies $(2x^{1/3}-1)(x^{1/3}+2)=0$
Now, $(2x^{1/3}-1)=0$
or, $(x^{1/3})^3=(\dfrac{1}{2})^3$
or, $x=\dfrac{1}{8}$
and $(x^{1/3}+2)=0$
or, $(x^{1/3})^3=(-2)^3$
or, $x=-8$
Solution set: $x=${$-8,\dfrac{1}{8}$}
