Answer
$\bf{Graph (b)}$
Work Step by Step
We have $x^{-2}-x^{-1}-6=0$
This implies $(x^{-1}-3)(x^{-1}+2)=0$
Thus, $x^{-1}=3 \implies \dfrac{1}{x}=3$
or, $x=\dfrac{1}{3}$
and $x^{-1}=-2\implies \dfrac{1}{x}=-2$
or, $x=\dfrac{-1}{2}$
To find the $x$-intercepts, we will have to take $f(x)=0$
Therefore,
Our desired $x$-intercepts are: {$\dfrac{-1}{2},\dfrac{1}{3}$}; which represents the $\bf{Graph (b)}$
