Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 636: 36


$\bf{Graph (b)}$

Work Step by Step

We have $x^{-2}-x^{-1}-6=0$ This implies $(x^{-1}-3)(x^{-1}+2)=0$ Thus, $x^{-1}=3 \implies \dfrac{1}{x}=3$ or, $x=\dfrac{1}{3}$ and $x^{-1}=-2\implies \dfrac{1}{x}=-2$ or, $x=\dfrac{-1}{2}$ To find the $x$-intercepts, we will have to take $f(x)=0$ Therefore, Our desired $x$-intercepts are: {$\dfrac{-1}{2},\dfrac{1}{3}$}; which represents the $\bf{Graph (b)}$
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