Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 26

{$-27,1$}

Since, $u^2+2u-3=0$ Factorize the expression as follows: $(u+3)(u-1)=0$ or, $u=${$-3,1$} Replace $u$ with $x^{1/3}$, we have $x^{1/3}=-3\implies x=-3^3$ $x=-27$ and $x^{1/3}=1\implies x=1^3$ $x=1$ Hence, our solution set is $x=${$-27,1$}