Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 9



Work Step by Step

Since, $u^2-4u-21=0$ Factorize the expression as follows: $(u-7)(u+3)=0$ or, $u=${$-3,7$} Replace $u$ with $\sqrt x$, we have $\sqrt x=-3$ which has no solution. or, $\sqrt x=7 \implies x=7^2$ and $x=49$ Hence, our solution set is $x=${$49$}
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