Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 16


{$0,\pm \sqrt 5$}

Work Step by Step

Since, $u^2-u=6$ or, $u^2-u+6=0$ Factorize the expression as follows: $(u-3)(u+2)=0$ or, $u=${$-2,3$} Replace $u$ with $x^2-2$, we have $x^2-2=-2 \implies x=0$ and $x^2-2=3 \implies x^2=5$ or, $x=\pm \sqrt 5$ Hence, our solution set is $x=${$0,\pm \sqrt 5$}
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