Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 7



Work Step by Step

Since, $u^2+u-2=0$ Factorize the expression as follows: $(u+2)(u-1)=0$ or, $u=${$-2,1$} Replace $u$ with $\sqrt x$, we have $\sqrt x=-2$ which has no solution. or, $\sqrt x=1$ and $x=1$ Hence, our solution set is $x=${$1$}
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