Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 18

Answer

{$-2,-1,3,4$}

Work Step by Step

Since, $u^2-11u+24=0$ Factorize the expression as follows: $(u-8)(u-3)=0$ or, $u=${$3,8$} Replace $u$ with $x^2-2x$, we have $x^2-2x=3 \implies x^2-2x-3=0$ or, $(x-3)(x+1)=0$ $x=${$-1,3$} and $x^2-2x=8 \implies x^2-2x-8=0$ or, $(x-4)(x+2)=0$ $x=${$-2,4$} Hence, our solution set is $x=${$-2,-1,3,4$}
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