Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 6

Answer

{$ \pm \sqrt 5i,\pm 1$}

Work Step by Step

Since, $u^2+4u=5$ or, $u^2+4u-5=0$ Factorize the expression as follows: $(u+5)(u-1)=0$ or, $u=${$-5,1$} Replace $u$ with $x^2$, we have $x^2=-5 \implies x=\pm \sqrt {-5}$ or, $x=\pm \sqrt 5i$ and $x^2=1$ This implies that $x= \pm \sqrt 5i,\pm 1$ Hence, our solution set is $x=${$ \pm \sqrt 5i,\pm 1$}
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