Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.4 - Equations Quadratic in Form - Exercise Set - Page 635: 12

Answer

{$36$}

Work Step by Step

Since, $2u^2-7u-30=0$ Factorize the expression as follows: $(2u+5)(u-6)=0$ or, $u=${$\dfrac{-5}{2},6$} Replace $u$ with $\sqrt x$, we have $\sqrt x=\dfrac{-5}{2}$ which has no solution and $\sqrt x=6 \implies x=6^2$ or, $x=36$ Hence, our solution set is $x=${$36$}
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