Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 9

Answer

{$\dfrac{1- \sqrt{7}}{6},\dfrac{1 + \sqrt{7}}{6}$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Since, $6x^2-2x-1=0$ Thus, $x=\dfrac{-(-2) \pm \sqrt{(-2)^2-4(6)(-1)}}{2(6)}$ or, $x=\dfrac{2 \pm \sqrt{28}}{12}$ or, $x=\dfrac{1 \pm \sqrt{7}}{6}$ or, $x=\dfrac{1- \sqrt{7}}{6},\dfrac{1 + \sqrt{7}}{6}$ Our solution set is: {$\dfrac{1- \sqrt{7}}{6},\dfrac{1 + \sqrt{7}}{6}$}
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