Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 2



Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Given: $x^2+8x+15=0$ Thus, $x=\dfrac{-8 \pm \sqrt{(8)^2-4(1)(15)}}{2(1)}$ or, $x=\dfrac{-8 \pm 2}{2}$ or, $x=\dfrac{-8 + 2}{2}=-3$ and $x=\dfrac{-8 -2}{2}=-5$ Our solution set is: {$-3,-5$}
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