Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 11


{$\dfrac{3}{8}-\dfrac{\sqrt{87}}{8}i,\dfrac{3}{8} + \dfrac{\sqrt{87}}{8}i$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Since, $4x^2-3x+6=0$ Thus, $x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(4)(6)}}{2(4)}$ or, $x=\dfrac{3 \pm \sqrt{-87}}{8}$ or, $x=\dfrac{3}{8} \pm \dfrac{\sqrt{87}}{8}i$ or, $x=\dfrac{3}{8}-\dfrac{\sqrt{87}}{8}i,\dfrac{3}{8} + \dfrac{\sqrt{87}}{8}i$ Our solution set is: {$\dfrac{3}{8}-\dfrac{\sqrt{87}}{8}i,\dfrac{3}{8} + \dfrac{\sqrt{87}}{8}i$}
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