Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 18


{$\dfrac{-3}{2} ,-1$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ As we are given that $2x^2+8x=3x-3$ or, $2x^2+8x-3x+3=0$ This implies $2x^2+5x+3=0$ Thus, $x=\dfrac{-(5) \pm \sqrt{(5)^2-4(2)(3)}}{2(2)}$ or, $x=\dfrac{-5 \pm \sqrt{1}}{4} \implies x= \dfrac{-5 \pm 1}{4}$ or, $x=\dfrac{-5 - 1}{4},\dfrac{-5 + 1}{4}$ Our solution set is: {$\dfrac{-3}{2} ,-1$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.