Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 5


{$\dfrac{-3 - \sqrt{89}}{2},\dfrac{-3 + \sqrt{89}}{2}$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Given: $x^2+3x-20=0$ Thus, $x=\dfrac{-(3) \pm \sqrt{(3)^2-4(1)(-20)}}{2(1)}$ or, $x=\dfrac{-3 \pm \sqrt{89}}{2}$ or, $x=\dfrac{-3 - \sqrt{89}}{2}$ and $x=\dfrac{-3 + \sqrt{89}}{2}$ Our solution set is: {$\dfrac{-3 - \sqrt{89}}{2},\dfrac{-3 + \sqrt{89}}{2}$}
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