Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 16


{$\dfrac{2}{3} - \dfrac{ \sqrt{14}}{3}i,\dfrac{2}{3}+\dfrac{ \sqrt{14}}{3}i$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Since, $3x^2-4x+6=0$ Thus, $x=\dfrac{-(-4) \pm \sqrt{(-4)^2-4(3)(6)}}{2(3)}$ or, $x=\dfrac{4 \pm \sqrt{-56}}{6}$ or, $x=\dfrac{2}{3} \pm \dfrac{ \sqrt{14}}{3}i$ or, $x=\dfrac{2}{3} - \dfrac{ \sqrt{14}}{3}i,\dfrac{2}{3}+\dfrac{ \sqrt{14}}{3}i$ Our solution set is: {$\dfrac{2}{3} - \dfrac{ \sqrt{14}}{3}i,\dfrac{2}{3}+\dfrac{ \sqrt{14}}{3}i$}
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