Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 10


{$\dfrac{-2 -\sqrt{14}}{2},\dfrac{-2 + \sqrt{14}}{2}$}

Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Since, $2x^2+4x-5=0$ Thus, $x=\dfrac{-(4) \pm \sqrt{(4)^2-4(2)(-5)}}{2(2)}$ or, $x=\dfrac{-4 \pm \sqrt{56}}{4}$ or, $x=\dfrac{-2 \pm \sqrt{14}}{2}$ or, $x=\dfrac{-2 -\sqrt{14}}{2},\dfrac{-2 + \sqrt{14}}{2}$ Our solution set is: {$\dfrac{-2 -\sqrt{14}}{2},\dfrac{-2 + \sqrt{14}}{2}$}
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