Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 607: 4



Work Step by Step

Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ Given: $5x^2+8x=-3$ It can be written as: $5x^2+8x+3=0$ Thus, $x=\dfrac{-(8) \pm \sqrt{(8)^2-4(5)(3)}}{2(5)}$ or, $x=\dfrac{-8 \pm 2}{10}$ or, $x=\dfrac{-8 + 2}{10}=\dfrac{-3}{5}$ and $x=\dfrac{-8-2}{10}=-1$ Our solution set is: {$-1,\dfrac{-3}{5}$}
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