Answer
{$\dfrac{-5 - \sqrt{65}}{2},\dfrac{-5 + \sqrt{65}}{2}$}
Work Step by Step
Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$
Given: $x^2+5x-10=0$
Thus, $x=\dfrac{-(5) \pm \sqrt{(5)^2-4(1)(-10)}}{2(1)}$
or, $x=\dfrac{-5 \pm \sqrt{65}}{2}$
or, $x=\dfrac{-5 - \sqrt{65}}{2},\dfrac{-5 + \sqrt{65}}{2}$
Our solution set is: {$\dfrac{-5 - \sqrt{65}}{2},\dfrac{-5 + \sqrt{65}}{2}$}
