Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set: 59

Answer

$\dfrac{3\sqrt[4]{x^3}}{x}$

Work Step by Step

RECALL: For any non-negative real number $a$, $\sqrt[4]{a^4}= a$ Rationalize the denominator by multiplying $\sqrt[4]{x^3}$ to both the numerator and the denominator. Simplify using the rule above to obtain: $\require{cancel} =\dfrac{3 \cdot \sqrt[4]{x^3}}{\sqrt[4]{x} \cdot \sqrt[4]{x^3}} \\=\dfrac{3\sqrt[4]{x^3}}{\sqrt[4]{x^4}} \\=\dfrac{3\sqrt[4]{x^3}}{x}$
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