Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 550: 49



Work Step by Step

RECALL: For any real number $a$, $\sqrt[3]{a^3}= a$ Rationalize the denominator by multiplying $3^2$ to both the numerator and the denominator of the radicand. Simplify using the rule above to obtain: $\require{cancel} =\sqrt[3]{\dfrac{2(3^2)}{3(3^2)}} \\=\sqrt[3]{\dfrac{2(9)}{3^3}} \\=\frac{1}{3}\sqrt[3]{18}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.