Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 550: 40



Work Step by Step

Rationalize the denominator by multiplying $\sqrt{3}$ to both the numerator and the denominator to obtain: $=\dfrac{\sqrt{7} \cdot \sqrt{3} }{\sqrt{3} \cdot \sqrt{3}} \\=\dfrac{\sqrt{7(3)}}{3} \\=\dfrac{\sqrt{21}}{3}$
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