Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set: 57

Answer

$\dfrac{\sqrt[3]{2x^2y}}{xy}$

Work Step by Step

RECALL: For any real number $a$, $\sqrt[3]{a^3}= a$ Rationalize the denominator by multiplying $x^2y$ to both the numerator and the denominator of the radicand. Simplify using the rule above to obtain: $\require{cancel} =\sqrt{\dfrac{2 \cdot x^2y}{xy^2 \cdot x^2y}} \\=\sqrt{\dfrac{2x^2y}{x^3y^3}} \\=\dfrac{\sqrt[3]{2x^2y}}{xy}$
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