Answer
$2\sqrt[3]{25}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $\sqrt[3]{5^2}$ to both the numerator and the denominator. Simplify using the rule above to obtain:
$\require{cancel}
=\dfrac{10 \cdot \sqrt[3]{5^2}}{\sqrt[3]{5} \cdot \sqrt[3]{5^2}}
\\=\dfrac{10\sqrt[3]{25}}{\sqrt[3]{5^3}}
\\=\dfrac{10\sqrt[3]{25}}{5}
\\=\dfrac{2\cancel{10}\sqrt[3]{25}}{\cancel{5}}
\\=2\sqrt[3]{25}$
