Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.5 - Multiplying with More Than One Term and Rationalizing Denominators - Exercise Set - Page 550: 43



Work Step by Step

RECALL: For all non-negative real number $a$, $\sqrt{a} \cdot \sqrt{a} = a$ Rationalize the denominator by multiplying $\sqrt3y$ to both the numerator and the denominator. Simplify using the rule above to obtain: $\require{cancel} =\dfrac{9 \cdot \sqrt{3y}}{\sqrt{3y} \cdot \sqrt{3y}} \\=\dfrac{9\sqrt{3y}}{3y} \\=\dfrac{\cancel{9}\sqrt{3y}}{\cancel{3}y} \\=\dfrac{3\sqrt{3y}}{y} $
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