## Intermediate Algebra for College Students (7th Edition)

$\sqrt[3]{x^{2}}+4\sqrt[3]{x}-21$
Use the FOIL method, along with $\sqrt[n]{a}\times\sqrt[n]{b}=\sqrt[n]{ab},\qquad$ $\sqrt[n]{a^{n}}=(\sqrt[n]{a})^{n}=a$ (for positive a). $F:\quad \sqrt[3]{x}\times\sqrt[3]{x}=\sqrt[3]{x^{2}}$ $O:\quad \sqrt[3]{x}\times 7=7\sqrt[3]{x}$ $I:\quad -3\times\sqrt[3]{x}=-3\sqrt[3]{x}$ $L:\quad -3\times 7=-21$ Add the terms (O and I are like terms...) $...$= $\sqrt[3]{x^{2}}+4\sqrt[3]{x}-21$