## Intermediate Algebra for College Students (7th Edition)

$\dfrac{\sqrt{10}}{5}$
Rationalize the denominator by multiplying $\sqrt{5}$ to both the numerator and the denominator to obtain: $=\dfrac{\sqrt{2} \cdot \sqrt{5} }{\sqrt{5} \cdot \sqrt{5}} \\=\dfrac{\sqrt{2(5)}}{5} \\=\dfrac{\sqrt{10}}{5}$