Intermediate Algebra for College Students (7th Edition)

$x^3y^4$
RECALL: (i) $\sqrt[n]{a} = a^{\frac{1}{n}}$ (ii) $\sqrt[n]{a^m} = a^{\frac{m}{n}}$ (iii) $(ab)^m = a^mb^m$ (iv) $(a^m)^n=a^{mn}$ Use the rules above to obtain: $=(x^{15}y^{20})^{\frac{1}{5}} \\=(x^{15})^{\frac{1}{5}}(y^{20})^{\frac{1}{5}} \\=x^{\frac{15}{5}}y^{\frac{20}{5}} \\=x^3y^4$