Answer
$\sqrt [15] {2x}$
Work Step by Step
Simplify. $\sqrt [5]{\sqrt[3] {2x}}$
Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$
Thus,
$\sqrt [5]{\sqrt[3] {2x}}=\sqrt[5] {(2x)^{\frac{1}{3}}}=((2x)^{\frac{1}{3}})^{\frac{1}{5}}$
or, $=(2x)^{\frac{1}{15}}$
or, $=\sqrt [15] {2x}$
