Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 108


$\sqrt [15] {2x}$

Work Step by Step

Simplify. $\sqrt [5]{\sqrt[3] {2x}}$ Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$ Thus, $\sqrt [5]{\sqrt[3] {2x}}=\sqrt[5] {(2x)^{\frac{1}{3}}}=((2x)^{\frac{1}{3}})^{\frac{1}{5}}$ or, $=(2x)^{\frac{1}{15}}$ or, $=\sqrt [15] {2x}$
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