Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 112


$\sqrt[4] ab$

Work Step by Step

Simplify. $\dfrac{\sqrt [4]{a^3b^3}}{\sqrt {ab}}$ Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$ Thus, $\dfrac{\sqrt [4]{a^3b^3}}{\sqrt {ab}}=\dfrac{(a^3b^3)^{\frac{1}{4}}}{(ab)^{\frac{1}{2}}}=(ab)^{\frac{3}{4}-\frac{1}{2}}$ or, $=(ab)^{\frac{1}{4}}$ or, $=\sqrt[4] ab$
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