## Intermediate Algebra for College Students (7th Edition)

$\frac{7x}{z^{\frac{1}{4}}}$
$z^{-\frac{1}{4}}$ is a non-zero real number thus $z^{-\frac{1}{4}}=\frac{1}{z^{\frac{1}{4}}}$ Thus $7xz^{-\frac{1}{4}}=\frac{7x}{z^{\frac{1}{4}}}$