Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 109



Work Step by Step

Simplify. $(\sqrt [4]{{x^3y^5}})^{12}$ Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$ Thus, $(\sqrt [4]{{x^3y^5}})^{12}=(x^3y^5)^{\frac{12}{4}}=(x^3y^5)^{3}$ or, $=(x^3)^{3}(y^5)^3$ or, $=x^{9}y^{15}$
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