## Intermediate Algebra for College Students (7th Edition)

$\dfrac{1}{y^{\frac{1}{6}}}$
Use the rule $(a^m)^n= a^{mn}$ to obtain: $=y^{-\frac{2}{3} \cdot \frac{1}{4}} \\=y^{-\frac{2(1)}{3(4)}} \\=y^{-\frac{2}{12}} \\=y^{-\frac{1}{6}}$ Use the rule $a^{-m} = \dfrac{1}{a^m}$ to obtain: $=\dfrac{1}{y^{\frac{1}{6}}}$