Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 71

Answer

$5x^2y^3$

Work Step by Step

RECALL: (1) $(a^m)^n=a^{mn}$ (2) $(ab)^m = a^mb^m$ (3) $a^{\frac{1}{n}}= \sqrt[n]{a}$ Use rule (2) above to obtain: $=25^{\frac{1}{2}}(x^4)^{\frac{1}{2}}(y^6)^{\frac{1}{2}}$ Use rules (1) and (3) above to obtain: $=\sqrt{25} x^{4(\frac{1}{2})}y^{6(\frac{1}{2})} \\=\sqrt{5^2}x^2y^3 \\=5x^2y^3$
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