Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 105


$\sqrt [4] {x^2y}$

Work Step by Step

Simplify. $\sqrt {\sqrt {x^2y}}$ Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$ Thus, $\sqrt {\sqrt {x^2y}}=\sqrt {(x^2y)^{\frac{1}{2}}}=((x^2y)^{\frac{1}{2}})^{\frac{1}{2}}$ or, $=(x^2y)^{\frac{1}{4}}$ ore, $=\sqrt [4] {x^2y}$
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