Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 57

Answer

$4$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}$ (ii) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$ Use the rules above to obtain: $=16^{\frac{3}{4} - \frac{1}{4}} \\=16^{\frac{2}{4}} \\=16^{\frac{1}{2}} \\=\sqrt{16} \\=4$
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