Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 77


$\frac{x}{3}$ and $x\ne2.$

Work Step by Step

$\frac{x^2-2x}{15}\div\frac{x-2}{5}=\frac{x(x-2)}{15}\frac{5}{x-2}=\frac{x}{3}$ and $x\ne2.$
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