Answer
$\frac{1}{x-3}$.
Work Step by Step
$\frac{x+1}{x^2-2x-3}=\frac{x+1}{x^2+x-3x-3}=\frac{x+1}{x(x+1)-3(x+1)}=\frac{x+1}{(x+1)(x-3)}=\frac{1}{x-3}$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 30
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