## Intermediate Algebra for College Students (7th Edition)

$x+5$ (and $x\ne5$).
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. Hence here: $\frac{x^2-25}{x-5}=\frac{x^2-5^2}{x-5}=\frac{(x+5)(x-5)}{x-5}=x+5$ (and $x\ne5$).