Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 43


$-\frac{x+3}{x+4}$ and $x\ne4$.

Work Step by Step

The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$. Hence here: $\frac{x^2-x-12}{16-x^2}=\frac{x^2+3x-4x-12}{-(x^2-4^2)}=\frac{x(x+3)-4(x+3)}{-(x+4)(x-4)}=\frac{(x+3)(x-4)}{-(x+4)(x-4)}=-\frac{x+3}{x+4}$ and $x\ne4$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.