Answer
$\frac{2}{5}$ and $x\ne2, x\ne-3.$
Work Step by Step
$\frac{x-2}{x+3}\frac{2x+6}{5x-10}=\frac{x-2}{x+3}\frac{2(x+3)}{5(x-2)}=\frac{2}{5}$ and $x\ne2, x\ne-3.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 52
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